22.51 Quantum Theory of Radiation Interactions, 2011 Final
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چکیده
100 years ago, in 1911, Rutherford explained the observed surprising behavior of alpha particles scattering from a gold foil, leading to the discovery of the nucleus. In this problem we want to derive from quantum-mechanics scattering theory the expression for Rutherford cross-section for electrons. The system is described by an electron and a nucleus, for convenience enclosed in a cavity of volume V = L. The interaction between the electron and the nucleus is the Coulomb interaction between the electron and the Z protons in the nucleus. You can use the following steps to calculate the scattering cross section dσ W = fi , with W 2π fi = n | (f |T |i) |2ρ(E ) f , Φ where T is the transition matrix and ρ(Ef ) the final density of states. inc
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تاریخ انتشار 2012